What's the need for the 220K grid load on the non-cascade channel? What does effectively strapping it across the 1M pot do?
In cascade mode, what does sending the signal to the wiper accomplish? I mean, why don't we see more setups like this, as opposed to the traditional signal out from the wiper. I think badcat does this too in places.
2 input question
Moderators: pompeiisneaks, Colossal
-
Smokebreak
- Posts: 1391
- Joined: Tue Dec 18, 2012 5:53 pm
- Location: Texas
2 input question
You do not have the required permissions to view the files attached to this post.
Re: 2 input question
I think it provides a lower impedance input using the 220K grid leak.
Notice the other one has a 1M grid leak resistor.
Notice the other one has a 1M grid leak resistor.
Tom
Don't let that smoke out!
Don't let that smoke out!
- martin manning
- Posts: 14308
- Joined: Sun Jul 06, 2008 12:43 am
- Location: 39°06' N 84°30' W
Re: 2 input question
When you plug into the low-gain, non-cascaded input the pot's element sets the input impedance seen by the guitar at 1M, where it should be. Wired the way it is, the pot is disabled when that input is in use. When you plug into the high-gain input, the pot sets the AC load on the input stage, and the paralleled 220k reduces it to a maximum of 180k. I'm guessing the purpose of this is to dirty it up with asymmetrical clipping.
Re: 2 input question
What I don't like so much of that configuration, and "so much" is a politically correct term, is that you'll face the highest attenuation of hi-mids with the lowest gain setting (I'm talking about hi gain input), while the minimum attenuation is at the gighest gain possible.
Just the opposite of what you usually want to thame the fizz.
Just the opposite of what you usually want to thame the fizz.
Re: 2 input question
Doublepost. Repetita sometimes doesn't iuvant sed just secant.