2 input question

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Smokebreak
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2 input question

Post by Smokebreak »

What's the need for the 220K grid load on the non-cascade channel? What does effectively strapping it across the 1M pot do?
In cascade mode, what does sending the signal to the wiper accomplish? I mean, why don't we see more setups like this, as opposed to the traditional signal out from the wiper. I think badcat does this too in places.
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Structo
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Re: 2 input question

Post by Structo »

I think it provides a lower impedance input using the 220K grid leak.

Notice the other one has a 1M grid leak resistor.
Tom

Don't let that smoke out!
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martin manning
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Re: 2 input question

Post by martin manning »

When you plug into the low-gain, non-cascaded input the pot's element sets the input impedance seen by the guitar at 1M, where it should be. Wired the way it is, the pot is disabled when that input is in use. When you plug into the high-gain input, the pot sets the AC load on the input stage, and the paralleled 220k reduces it to a maximum of 180k. I'm guessing the purpose of this is to dirty it up with asymmetrical clipping.
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roberto
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Re: 2 input question

Post by roberto »

What I don't like so much of that configuration, and "so much" is a politically correct term, is that you'll face the highest attenuation of hi-mids with the lowest gain setting (I'm talking about hi gain input), while the minimum attenuation is at the gighest gain possible.

Just the opposite of what you usually want to thame the fizz.
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roberto
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Re: 2 input question

Post by roberto »

Doublepost. Repetita sometimes doesn't iuvant sed just secant.
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