Hi everybody,
I was tinkering around with an "isolating" tube stage.
So of course I implemented a cathode follower first.
But this did not sound great (somewhat taking away the liveliness).
Then I build a split load with 56K at the plate and 56K + at the cathode, and 1 Meg to the grid.
Exactly like the Fender Deluxe 5e3 phase inverter.
I put a .1 cap on the plate and an indentical .1 cap on the cathode.
Then I connected both sides to a switch, so either side can feed the next stage (instead of the power tubes in this case).
I basically wanted to find out if the cathode follower indeed does sound the same as the signal on the plate.
In theorie it should be the same (just an inverted phase).
The signal on the plate sounds "normal", but if I connect the cathode cap to the next stage, the signal has less volume and it sounds very thin.
It is not a little difference, it is very audible. Especiall the thinner sound of the cathode follower.
Any explanation for that?
Or is there any another way to build a "buffer" with a tube other than a cathode follower?
Any hints appreciated!
Thanks a lot,
Stephan
split load phase inverter
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Stevem
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Re: split load phase inverter
Your dealing with impedance difference between signal pulled / taken off of those 2 points!
And a cathode follower output can not even provide unity gain too Boot!
The question needs to asked here as to what you are shooting for with your tinkering ?
And a cathode follower output can not even provide unity gain too Boot!
The question needs to asked here as to what you are shooting for with your tinkering ?
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Not screaming like the passengers in his car!
Cutting out a man's tongue does not mean he’s a liar, but it does show that you fear the truth he might speak about you!
Re: split load phase inverter
Maybe the amp is stable with the signal in one polarity, but not the other 
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Re: split load phase inverter
From what you say, you have put the signals out of phase, and they are cancelling - the thin sound is just the remainder of the two signals combined, because the two signals are not perfectly out of phase.