Regarding dropping string resistor calculations for my PI tube through V1
Voltage (E) = Current (I) * Resistance (R)
So if I'm right, I use 2.2ma per point(both triodes of a 12ax7) and the voltage that I want to drop right?
Example:
I want to drop an extra 15 volts from V3 (pi) so I get 6818 ohms. So I would take the value of the resistor already there (3300) and add the 6818 to it for a new resistor value of 10100, right? So I would just sub a 10k for the 3.3k that was there previously.
That seems really high compared to other peoples amp values. Am I missing something?
Disregard please....got answer in tech part of the forum.
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